Final answer to the airplane on a long treadmill problem ...

[ATK_Designs]

A plane DOES require velocity/speed to lift. The speed of the air over the top of the wing vs over the bottom of the wing creates a pressure difference and that is what gives you lift.

Wrong on the bolded part. How can a treadmill counteract the FORWARD push of the engines by spinning the wheels of a plane? All it does is spin the wheels. Answer me that. I just busted your theory, btw...

Again, for the 3rd time.

The plane's wheels are the same thing as the dyno's roller. It outputs no pwr or tq.

The treadmill does output HP and TQ, in negative direction.


So imagine it this way, instead of having your porsche sexing up on top of the dyno, this time, the dyno is doing a reverse cowboy (on top) on your porsche :idb:

Also: I said that the plan doesn't require the RIGHT velocity, not that it doesn't require ANY velocity at all. I was, however, wrong in the mean that it does require the velocity. What I meant was that it Does not require the exact same *book* velocity to lift off. Each plane is different and also in each situation (atmosphere density)