Quote Originally Posted by Ruiner
If you are so sure, then take a bet with me.

I will say this: you are wrong.

It IS NOT like your car on a dyno. In a car, the power goes to the wheels. In a plane, it "pushes" through the air via the engines. There is NO connection with the ground. BIG difference. Answer me this: how does a plane with sleds on the bottom take off in the snow? No wheels...

The plane, no matter how fast the treadmill is spinning, will push forward, THROUGH the air, and down the treadmill (that is as long as a runway). During that time, the plane will pick up speed and finally reach take off velocity.

If you don't believe me, bet me. It's VERY simple.
1. I said that plane = dyno roller, treadmill = car. Please reread what i said.

2. Plane will take off on snow since there AREN'T any -A Velocity on X axis with -hp & -tq. Also, the snow surface is STATIONARY has enough friction for the plane to grip on. Treadmill has -A Velocity on X axis with -hp & -tq. It counters every +A velocity in the +X direction.

3. Plane doesn't require right velocity/speed to lift off, it requires enough lift force of the air movement. It relies on its speed to help it move ALONG the density of the air to cause enough lift. If the plan is to run on the space runway where there aren't any air, it will not have any vertical movement. It will move VERY fast on the outerspace runway, but not UP unless it has a thrust engine to push it up and changes its Y directional velocity. The plane can run at 500mph on the runway while the air is moving at the SAME velocity and SAME force and SAME direction as the plane, it still WILL NOT take off.

I don't believe it bet. But I understand your concept very well.

It's time for the Mythbuster to prove this.

Also, the PLANE WILL TAKE OFF on the treadmill if it has this condition:

A thrust engine that creates +B velocity in +Y direction.

If its thrust engine only has purely +A Velocity in +X Direction, it WILL NOT take off.