Ideal volumetric efficiency
V_ideal = D*N/2
d= displacement
n= engine speed in rpm
so again
(ka24) 2389*7/2= 8,361.5
(rb25) 2498*8/2=9,992
(rb26) 2568*8/2=10,272
(sr20) 1998*8/2=7,992
So In order, the ideal volumetric effiency goes from sr20, ka24, rb25, rb26 (low to high)
Does this not also show that displacement is a huge factor?
Hope I used enough proof this time.





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