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Thread: Turn signal problem....

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  1. #1
    70hp FTL StraightSix's Avatar
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    Is the circuit for the turn signals fused? Could be as simple as a blown fuse.

    Also, the new signals are they a factory replacement part or aftermarket?

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    I've got a job... Killer's Avatar
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    Quote Originally Posted by StraightSix
    Is the circuit for the turn signals fused? Could be as simple as a blown fuse.

    Also, the new signals are they a factory replacement part or aftermarket?

    after market... and the bulbs do look smaller.. but i haven't checked the actual size...

    not a fuse.. if you read the thread i posted on the buell forum.. i have checked all fuses.... non are blown.

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    70hp FTL StraightSix's Avatar
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    Quote Originally Posted by Killer
    after market... and the bulbs do look smaller.. but i haven't checked the actual size...

    not a fuse.. if you read the thread i posted on the buell forum.. i have checked all fuses.... non are blown.
    I didn't read the Buell thread, obviously. Now that I have, I'm trying to think about how you would wire in a resistor, and what ohm value of resistor.

    In the turn signal circuit, the bulbs themselves are basically resistors. That's how they light up, well partially, they also need the vacuum inside the bulb. An ohmmeter will "see" the bulb as a resistor, though. If the bulbs you're using don't have enough resistance, that will also change the voltage in the overall circuit; this occurs because of Ohm's law where V = I*R, where V = voltage, I = current, and R = resistance. A change in one of those variables will cause a change in the others.

    I'll think on it and get back....

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    I've got a job... Killer's Avatar
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    Quote Originally Posted by StraightSix
    I didn't read the Buell thread, obviously. Now that I have, I'm trying to think about how you would wire in a resistor, and what ohm value of resistor.

    In the turn signal circuit, the bulbs themselves are basically resistors. That's how they light up, well partially, they also need the vacuum inside the bulb. An ohmmeter will "see" the bulb as a resistor, though. If the bulbs you're using don't have enough resistance, that will also change the voltage in the overall circuit; this occurs because of Ohm's law where V = I*R, where V = voltage, I = current, and R = resistance. A change in one of those variables will cause a change in the others.

    I'll think on it and get back....
    that'd be great...

    thanks!!! (i can't rep you... sorry )

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