Einstein's riddle - can you solve it?

[Atlblkz06]

ALBERT EINSTEIN'S RIDDLE

There are no tricks, just pure logic, so good luck and don't give up.

1. In a street there are five houses, painted five different colours.
2. In each house lives a person of different nationality
3. These five homeowners each drink a different kind of beverage, smoke different brand of cigar and keep a different pet.

THE QUESTION: WHO OWNS THE FISH?

Clues:
1. The Brit lives in a red house.
2. The Swede keeps dogs as pets.
3. The Dane drinks tea.
4. The Green house is next to, and on the left of the White house.
5. The owner of the Green house drinks coffee.
6. The person who smokes Pall Mall rears birds.
7. The owner of the Yellow house smokes Dunhill.
8. The man living in the centre house drinks milk.
9. The Norwegian lives in the first house.
10. The man who smokes Blends lives next to the one who keeps cats.
11. The man who keeps horses lives next to the man who smokes Dunhill.
12. The man who smokes Blue Master drinks beer.
13. The German smokes Prince.
14. The Norwegian lives next to the blue house.
15. The man who smokes Blends has a neighbour who drinks water.

Apparently Einstein wrote this and said that 98% of the world population, and 100% of the WL will not be able to solve it.

Hint: Make a grid.

Request: Please do not post the answer especially if all you're going to do is google it!

[BobbyFresco]

The German.

[Atlblkz06]

quod erat demonstrandum...bravo!

[BobbyFresco]

quod erat demonstrandum...bravo!

The riddle in question is nothing new.
LOL @ posting it on here, however...:lmfao:

[Atlblkz06]

The lolz are in the irony somewhere in a WL sorta way. Thats the whole point damn it lol

[RandomGuy]

the mexican

[Jason..]

the mexicanYou can change your sig now..

[hondachik]

reps to you OP. I used to LOVE these type of logic puzzles in school. I used to always work them until I get it right. Usually I was first or second to complete them correctly. Anyways I copied all the info, bout to draw my grid out (that may be the harder part...considering I've never had to draw one), and when I get finished should I just PM you the answer? I'm assuming you do have it.

[stillaneon]

reps to you OP. I used to LOVE these type of logic puzzles in school. I used to always work them until I get it right. Usually I was first or second to complete them correctly. Anyways I copied all the info, bout to draw my grid out (that may be the harder part...considering I've never had to draw one), and when I get finished should I just PM you the answer? I'm assuming you do have it.

I finished it.

The Grid is a little harder than I expected because there is very little information given at once.

I just drew five "houses" and went fomr there.

That gave me the order of the houses and all.

[Jason..]

I finished it.

The Grid is a little harder than I expected because there is very little information given at once.

I just drew five "houses" and went fomr there.

That gave me the order of the houses and all.How did I know you were gonig to post in here lol.

[Complication]

Just finished it. It took a while. I was stuck at one point... all I could get was:

-Norwegian-yellow house- dunhill- xxxxxx- xxxxxx
-Xxxxxxxxx- Blue house - xxxxxx- Horses- xxxxxx
- Brit - Red house - xxxxxxx- xxxxxx- xxxxxx
- xxxxxxx - Green House - xxxxxx - xxxxxx - xxxxx
-xxxxxxx - White house- xxxxxxx- xxxxxxx- xxxxxx

After I realized I had the position of the houses I went with that and finally got it.

[stillaneon]

How did I know you were gonig to post in here lol.

Cause I was bored and enjoy logic puzzles

[hondachik]

So like, I did the grid. OMG that crap was hard. But uh, I PM'd the OP and I'm waiting for his reply to see if I has it right. According to his profile he hasn't been active since 12:34pm....sooo I may not find out if I'm right til much later. :(

[willum14pb]

german

[hondachik]

german

....




Anyways...time for another one. Maybe I should go try and find some logic websites.


edit: yay

http://www.puzzles.com/projects/LogicProblemsArchive.html

[AirMax95]

yay........


Now another

[Atlblkz06]

*What is the largest possible number you can write using only 2 numbers - just 2 numbers, no other mathematical symbols?

Since we're talking about numbers, here is a fact for you: .99999...(repeating infinitely) = 1.

Feel free to post up other stuff if you find anything good.

[hondachik]

eh..since we went to numbers, thy may pass. Me + math = FTL

[Magnus213]

Since we're talking about numbers, here is a fact for you: .99999...(repeating infinitely) = 1.
Can I see that proof?

[Atlblkz06]

The easy way:
x = .999…
10x = 9.999…
10x - .999… = 9
9x = 9
x = 1
.999… = 1

Other way:

Lets say y is the .99999 number of finite number of 9's (n).
For any y, there is a y1 such that y<y1<1.
We know that y limits to 1 as n goes to infinity, and therefore so does y1 and they're both 1.

If you pick a number thats closer to 1 than my .999999 (n times), I'll simply pick a number closer to 1. We'll do this infinitely until we both end up with 1.

The kicker is that you're doing this infinitely and thats something thats hard to imagine.

[AnthonyF]

Who wants to own a damn fish?

-Ant.

[Magnus213]

The easy way:
x = .999…
10x = 9.999…
10x - .999… = 9
9x = 9
x = 1
.999… = 1

Other way:

Lets say y is the .99999 number of finite number of 9's (n).
For any y, there is a y1 such that y<y1<1.
We know that y limits to 1 as n goes to infinity, and therefore so does y1 and they're both 1.

If you pick a number thats closer to 1 than my .999999 (n times), I'll simply pick a number closer to 1. We'll do this infinitely until we both end up with 1.

The kicker is that you're doing this infinitely and thats something thats hard to imagine.
I still don't like this. y and y1 will continually subdivide and approach 1 and all that, but "and they're both 1" and "we both end up with 1" don't prove that they become one. The number will just get infinitely close to 1 and infinitely longer on paper, but never actually get there.

I feel like something fishy is going on with the numerical proof as well. Let's assume that n = 6, so x = 0.999999. Pretty close to 1, clearly not infinitely close, but let's go with it.

x = 0.999999
10x = 9.99999 (notice that you lose a decimal place value)
10x - 0.999999 = 9.99999 - 0.999999 = 8.999991
9x = 9(0.999999) = 8.999991 =/= 9
x =/= 1

I don't see how you can fundamentally say that two distinctly different numbers have the same value.

[Atlblkz06]

I still don't like this. y and y1 will continually subdivide and approach 1 and all that, but "and they're both 1" and "we both end up with 1" don't prove that they become one. The number will just get infinitely close to 1 and infinitely longer on paper, but never actually get there.

I feel like something fishy is going on with the numerical proof as well. Let's assume that n = 6, so x = 0.999999. Pretty close to 1, clearly not infinitely close, but let's go with it.

x = 0.999999
10x = 9.99999 (notice that you lose a decimal place value)
10x - 0.999999 = 9.99999 - 0.999999 = 8.999991
9x = 9(0.999999) = 8.999991 =/= 9
x =/= 1

I don't see how you can fundamentally say that two distinctly different numbers have the same value.

For part A, think in terms of limits, not any finite point in time. You cannot "freeze" the process at any point and check to see if it works.

Part B, same thing. the 9s never stop repeating (hence the 3 dots)
10x-x = 9x, not 8.999x :)

Good points though - but let me assure you that this stuff is true. I did NOT just create this proof, its a "well known fact". Juts check online or ask any math professor.

[hondachik]

lmao @ IA turned into a math website. Srsly. Not many people are good at math =)

[man]

Since we're talking about numbers, here is a fact for you: .99999...(repeating infinitely) = 1.

Merely a myth based on loose math, not a true fact

[redrumracer]

You can change your sig now..
yes instead it just says the server is too busy

[Atlblkz06]

Merely a myth based on loose math, not a true fact

Loose math? There is no such thing. If you think it is not true, prove it.

[redrumracer]

as x approaches 0 it goes to infinity end math lesson.

[man]

Loose math? There is no such thing. If you think it is not true, prove it.

If Sn is the summation of 9/(10^n) from n=0 to n=inf.
then
1 = the limit as n->inf of Sn

Calc 2 at it's best, convergence... lol, takes me back to sophomore year.

[ShooterMcGavin]

not bored enough to do this right now but these puzzles are pretty fun...and there are some that get stupid (as in have like 12-15 variables).

[Atlblkz06]

If Sn is the summation of 9/(10^n) from n=0 to n=inf.
then
1 = the limit as n->inf of Sn

Calc 2 at it's best, convergence... lol, takes me back to sophomore year.

lol yea good time (not). Hated calculus when I took it, learned to like it later in other math classes.

So umm the limit of Sn = 0 as n-> inf. You're dividing 9 by a 10^n which explodes as n-> inf.

[man]

lol yea good time (not). Hated calculus when I took it, learned to like it later in other math classes.

So umm the limit of Sn = 0 as n-> inf. You're dividing 9 by a 10^n which explodes as n-> inf.

how does it explode, it continuously approaches 1

9/10^1 = .9 + 9/10^2 = .99 + 9/10^3 = .999 etc...

[Atlblkz06]

Oh I missed the part where you said summation. PMing - doubt anyone else cares.

[Magnus213]

Got damn infinity.