math help?

[Nubz]

matrices are a bitch
help would be nice

a total of twelve thousand passengers normally ride the greenline of the MBTA during the morning rush hour. The token prices for a ride 25 cent child under 12, adult=1 and senior=50cents. revenue=10,700. price raise 35 child, 1.50=adult and 50cent=senior and revenue would be 15,820. how many riders in each category normally ride the green line during the morning hour

anyone know how to do this
i have the
.25x+1y+.50z=10700 and .35x+1.50y+.50z=15820
but i dont know what to do after

[Friggintitsman]

shit stained balls

[Nubz]

yeah. i hate math. i need some help

[Friggintitsman]

I think the proper pronunciation here in the south is Maf

[Nubz]

well help me with my maf

[x Resilience]

I think the proper pronunciation here in the south is Maf


Bwhahahahahhahahahahahahhahaha!

[Friggintitsman]

Ask Bobbyfresh he seems like a smart guy.

[gtrmonkey]

Well you probably could set it up in a matrix? But it been awhile since I even done that.

[Nubz]

thats the problem. i get it all set up and then idk what to do after

[gtrmonkey]

http://answers.yahoo.com/question/index?qid=20061031195116AA9x0G7

[Nubz]

that actually confused me.

[Friggintitsman]

Currently Active Users Viewing This Thread: 6 (6 members and 0 guests)
Friggintitsman, BobbyFresh, 89_Stallion, VWGirl, ironchef, x Resilience

Don't let bobby leave

[Nubz]

i messaged him. he cant do it either

[BobbyFresco]

LOL...I haven't done this stuff in years but Im still fucking with it...

[Nubz]

you can do itttttt

[mad3nch1na]

this is pretty easy, you just gota subsitute...

[Nubz]

then help me out...

[keevo54]

matrices are a bitch
help would be nice

a total of twelve thousand passengers normally ride the greenline of the MBTA during the morning rush hour. The token prices for a ride 25 cent child under 12, adult=1 and senior=50cents. revenue=10,700. price raise 35 child, 1.50=adult and 50cent=senior and revenue would be 15,820. how many riders in each category normally ride the green line during the morning hour

anyone know how to do this
i have the
.25x+1y+.50z=10700 and .35x+1.50y+.50z=15820
but i dont know what to do after
x+y+z=12000....then substitute

[Nubz]

what exactly do i substitute. you have to forgive my stupidness.

[VWGirl]

LOL...I haven't done this stuff in years but Im still fucking with it...

Yeah it's been ten years for me... so it's like staring at a blank wall...

isn't it just a multivariable equation tho and not a matrix?

[gtrmonkey]

you can set it up in an matrix. The keevo54 help him figture out he final piece of the pluzze

[Friggintitsman]

I left my job as a rocket scientist to pursue a new one as a male stripper.

[Nubz]

keevo54. solve it man

[VWGirl]

I keep getting not whole numbers... and i don't think there are fractions of people...

[BobbyFresco]

keevo54. solve it man


Ok...so with the clue Keevo gave, it refreshed my memory...It really isnt that hard....and you're not gonna learn with someone handing you the answer...and this is nothing compared to what you have to look forward to....Just stop and think for a minute, given the info you have bro.

[VWGirl]

uggg i got it finally too :)

[BobbyFresco]

If you want an easy out, google matrix solvers...and go from there..

[VWGirl]

keevo54. solve it man

How are you setting it up? You can solve this if i can... I haven't taken a math course in at least 7 years

[Nubz]

im drawing total blanks.

[VWGirl]

im drawing total blanks.

so with keevo's help... you should have

.25x+1y+.50z= 10700
.35x+1.50y+.50z=15820
x+y+z=12000

right?

[Nubz]

correct

[VWGirl]

OK, so now you need to break it down so that you can get the value of one ... you start by breaking the equations down...

.25 1 .5 10700 x4-> 1 4 2 42800
.35 1.5 .5 15820 .35 1.5 .5 15280
1 1 1 12000 1 1 1 12000

[VWGirl]

yeah.. that looked a lot better when i typed it in this box... but basically i just multiplied the first row by 4 to get whole #'s see... you don't want the fraction/decimals

[VWGirl]

so next operation... you want to make the x of the second equation 0 out... how would you do this?

[K20Z1]

is it... [x y z] x [x coefficient y coefficient z coefficient] ^-1 [## ]<--- enter that in calculator

[VWGirl]

is it... [x y z] x [x coefficient y coefficient z coefficient] ^-1 [## ]<--- enter that in calculator

wtf is a calculator? don't you have to show work for this shiz?

They wouldn't even let us have calculators out in class for this back in the day

[GLulic]

whoaaaaaa you guys are blowing my mind on here..
lol what grade are guys in?

[VWGirl]

whoaaaaaa you guys are blowing my mind on here..
lol what grade are guys in?

grades? I'm like a 5th or 6th year senior with 140+ cr hrs :screwy:

[90_ACCORD]

shit dude remember when i told you i forgot one and thats why i could do it. thats the one i forgot right there.

the x+y+z=12000

[90_ACCORD]

so with keevo's help... you should have

.25x+1y+.50z= 10700
.35x+1.50y+.50z=15820
x+y+z=12000

right?'

thats correct. its all coming back to me now.

[Atlblkz06]

Are you supposed to use algebra or linear algebra to solve this?
Use 1000, 10000 and 900 and you'll get pretty close. Tweak it and you have the answer.

Markov chains - steady state vectors... god damn it, I don't remember how to do this. Look it up online? lol

[integraboi88]

Just punch in the numbers on your TI83 plus calculator(problem solved).

[VWGirl]

Are you supposed to use algebra or linear algebra to solve this?
Use 1000, 10000 and 900 and you'll get pretty close. Tweak it and you have the answer.

Markov chains - steady state vectors... god damn it, I don't remember how to do this. Look it up online? lol

Why would you plug those numbers in? It's not a guessing game... and I would not call those numbers close anyway...

[staysideways]

grades? I'm like a 5th or 6th year senior with 140+ cr hrs :screwy:

all those hours and you don't know what year you are?

i was close to figuring out the answer but i gave up because i have to go to work.

sorry broseph

[GLulic]

ohh you stole the sammich mans girl..lol i wonder what he'll do:ninja:

[Atlblkz06]

Why would you plug those numbers in? It's not a guessing game... and I would not call those numbers close anyway...

I agree, its not a guessing game - I just wanted to give him some numbers close to the answer so he could understand that there is only one combination that can satisfy both since one of the prices is constant.

Using x= 1k, y=10k, z = 900:
.25x + 1y + .5z = 10700 (correct)
.35x + 1.5y + .5z = 15800 (off by $20)

How is that not close?

[Princess12]

A little rusty, but this is my opinion.

.25x+1y+.50z= 10700
.35x+1.50y+.50z=15820
_________________________
.60x+2.5y+1z=26520

I would get rid of decimals by multiplying by 10
10 (.6x+2.5y+z)=26520(10)
6x+25y+10z=265200

Now, solve for each variable so you are using common factors.
x=(265200-25y-10z)/6

((265200-25y-10z)/6))+25y-10z=265200

etc... It will work out this way.

OR
Plug the factors into the matrix function on your calculator.

[keevo54]

so with keevo's help... you should have

.25x+1y+.50z= 10700
.35x+1.50y+.50z=15820
x+y+z=12000

right?

u can use a calculator and do it with matrix or...

x=12000-y-z.......substitute to the first two equations
.25(12000-y-z)+1y+.5z=10700
.35(12000-y-z)+1.5y+.5z=15820

multiply it out and now u have 2 variables and can solve easy...once u have y and z.......u can plug it back in for x

[VWGirl]

anyway... i gave him the answers last night cause i was tired and he wasn't getting it... so he has the right answers... it's his own fault when he doesn't understand how to do it to pass a test or move on to the next course

[Atlblkz06]

Can someone tell me how to use markov chains to solve this?

[VWGirl]

all those hours and you don't know what year you are?

i was close to figuring out the answer but i gave up because i have to go to work.

sorry broseph

well... for my current BA degree I'd be a senior... but that's two associates degrees and then some... and three different schools in two different states...

so really i will have enough credit hours by the time i get my BA to have my MA...