who wants to do some physics

[Benefit]

http://i12.tinypic.com/6jntidl.jpg

[GIXXERDK]

Is this for online test?

[Benefit]

no my girl asked me to see if i can do it

[SL65AMG]

uuuuhhhhh.... i have only taken one physics class and that was ..... **** 4 years ago. in highschool..... so NO i do not want to do any physics nor can i solve that problem....


i dont have a clue where to begin

[imbosile]

I would do it, but I just got out of a physics test about 20 minutes ago so i'm not exactly in the mood. maybe tomorrow, i'm sure i can find someone around here willing to do it.

[SloWRX]

the fuk is ur problem! lol

[xb1]

and can you? i can.

[Benefit]

lmao

[changaroo]

cent force = mv^2 / R

theres a starting point :D

[SL65AMG]

cent force = mv^2 / R

theres a starting point :D


(mass)*(Velocity) ^ 2(squared)
____________________________

(radius???)


im guessing this is wrong because you cannot obtain ANY of this information from the drawing...... except the ^2 and the / part

[xb1]

and don't forget acceleration of gravilty and its effect at different points on the circle.

[changaroo]

yes :) lolol, all this reminds me of physics 1. phys 2 blows bum bum.

in uniform circular motion, centripetal force = tension

[Benefit]

wtf r u guys talking about

[Magnus213]

1. For both balls, you have a gravity force vector pointing directly down. The other vector is a tension vector pointing directly to the center of the circle, it'll be different for each.

2. At the top, you have tension and gravity vectors both directed toward the center of the circle. At the very minimum speed, you'll have no tension and it'll only be gravity acting on the ball. The gravity force will have to be equal to the value of the centripetal force.
mg = (mv^2)/r
gr = v^2
v(min) = root(gr)

3. At the bottom, tension is directed directly upward and gravity is opposite (straight down). The sum of these forces is equal to the centripetal force again.
T(max) - F(g) = [mv(max)^2]/r
r[T(max) - F(g)] = mv(max)^2
v(max) = root{[r(T(max)-mg)]/m}

4. If the ball breaks at P it moves according to the tangential velocity vector at that point, which is directed straight up. So, the ball will fly directly up into the air, slow down, and fall back to the ground according to 1-D kinematics.

Someone else check me. I have an odd feeling that I didn't do 2 and 3 correctly. If this really was for an online test, screw you for cheating. If not, good luck.

[Psycho]

The answer is D.

[Benefit]

lmao @ psycho....and wow magnus , repped

[§treet_§peed]

dude i jsut got a ****ing head ache from reading that ****. i haven't done that **** since high school and hell i was drunk as **** most of them time but however i passed with flying colors lol:D

[Annihilation]

the answer is 7

[§treet_§peed]

i thought it was tree fiddy

[Spektrewing386]

i think i got the tension on #1 correct. Oh and i forgot to isolate the desired variable for the 'expression', but thats easy.
http://upshizzle.com/pfiles/5859/Untitled-1.jpg

[tightflks]

you go to ga tech? if so i should have the answers some where

[TRDwasiq]

Answer is V-tec>tension

[Spektrewing386]

just gotta know that Force = mass*acceleration and that if an object isnt moving in a particular direction (up/down/left/right) then force=force

basically thats chapters 1-8 in most physics books. its what the force is (tension, pushing, pulling, torque) and what the acceleration is (rotational, linear) is what makes the chapters different.


dont forget projectial motion, thats part of those chapters too.

[Magnus213]

I love physics.

That is all.